What is derivative of f(x)=-2t^2+3t-6 ?

The answer to derivative of f(x)=-2t^2+3t-6 is (dt)/(dx)=0

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derivative of f(x)=-2t^2+3t-6

derivative of

f (x) = - 2 t^{2} + 3 t - 6

\frac{d t}{d x} = 0

Solution steps

f (x) = - 2 t^{2} + 3 t - 6

Treat

t

t (x)

Differentiate both sides:

0 = 3 \frac{d t}{d x} - 4 t \frac{d t}{d x}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

\frac{d}{d x} (\frac{d y}{d x}) + y = 1

\frac{3 s + 2}{s ^{2} + 2 s + 10}

2 a x + b

x \to 5 lim (\frac{( x + 1 )}{x - 5})

\int tan (\frac{x}{3}) d x

What is derivative of f(x)=-2t^2+3t-6 ?
The answer to derivative of f(x)=-2t^2+3t-6 is (dt)/(dx)=0