What is the solution for y^{''}-6y^'+11y=0 ?

The solution for y^{''}-6y^'+11y=0 is y=e^{3t}(c_{1}cos(sqrt(2)t)+c_{2}sin(sqrt(2)t))

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y^{''}-6y^'+11y=0

y^{^{''}} - 6 y^{^{'}} + 11 y = 0

y = e^{3 t} (c_{1} cos (2 t) + c_{2} sin (2 t))

Solution steps

y^{''} (t) - 6 y^{'} (t) + 11 y = 0

Solve linear ODE:

y = e^{3 t} (c_{1} cos (2 t) + c_{2} sin (2 t))

y = e^{3 t} (c_{1} cos (2 t) + c_{2} sin (2 t))

n = 0 \sum \infty \frac{1}{n + 11}

y = sin^{2} (x)

\int 4 sin (4 x) d x

f (x) = \frac{- 1}{x}, at x = 16

\int sin (6 x) - 7 sin (7 x) d x

What is the solution for y^{''}-6y^'+11y=0 ?
The solution for y^{''}-6y^'+11y=0 is y=e^{3t}(c_{1}cos(sqrt(2)t)+c_{2}sin(sqrt(2)t))