What is the tangent of f(x)=1-tan(x),\at x=-pi/4 ?

The tangent of f(x)=1-tan(x),\at x=-pi/4 is y=-2x+2-pi/2

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tangent of f(x)=1-tan(x),\at x=-pi/4

tangent of

f (x) = 1 - tan (x), at x = - \frac{π}{4}

y = - 2 x + 2 - \frac{π}{2}

Solution steps

Find the tangent point:

(- \frac{π}{4}, 2)

Find the slope of

f (x) = 1 - tan (x) : \frac{df ( x )}{d x} = - sec^{2} (x)

Compute the slope of

f (x) = 1 - tan (x)

x = - \frac{π}{4} : m = - 2

Find the line with slope m=

- 2

and passing through

(- \frac{π}{4}, 2) : y = - 2 x + 2 - \frac{π}{2}

y = - 2 x + 2 - \frac{π}{2}

\int 7 e^{2 x} d x

\frac{d y}{d x} = \frac{( y - 1 )}{y + x}

\frac{( s - 1 )}{s \cdot ( s ^{2} + s + 1 )}

\int \frac{x ^{5}}{( 1 + x ^{3} ) ^{\frac{5}{2}}} d x

\int cos (x - n x) d x

What is the tangent of f(x)=1-tan(x),\at x=-pi/4 ?
The tangent of f(x)=1-tan(x),\at x=-pi/4 is y=-2x+2-pi/2