What is the tangent of 3sec(x),\at x= pi/6 ?

The tangent of 3sec(x),\at x= pi/6 is y=2x+2sqrt(3)-pi/3

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tangent of 3sec(x),\at x= pi/6

tangent of

3 sec (x), at x = \frac{π}{6}

y = 2 x + 23 - \frac{π}{3}

Solution steps

Find the tangent point:

(\frac{π}{6}, 23)

Find the slope of

y = 3 sec (x) : \frac{d y}{d x} = 3 sec (x) tan (x)

Compute the slope of

y = 3 sec (x)

x = \frac{π}{6} : m = 2

Find the line with slope m=

2

and passing through

(\frac{π}{6}, 23) : y = 2 x + 23 - \frac{π}{3}

y = 2 x + 23 - \frac{π}{3}

\int_{0}^{3} x^{4} d x

y^{^{''}} - 4 y = 24 t e^{(- 2 t)} + 2 e^{(- 2 t)} + 8 - 8 t

x \to 4 lim (x^{2} + 5 x)

\int e^{- 3 x} cos (x) d x

\int (2 x + 1) csc (x^{2} + x) cot (x^{2} + x) d x

What is the tangent of 3sec(x),\at x= pi/6 ?
The tangent of 3sec(x),\at x= pi/6 is y=2x+2sqrt(3)-pi/3