What is the integral of (\sqrt[3]{x})/(x^2) ?

The integral of (\sqrt[3]{x})/(x^2) is -3/(2x^{2/3)}+C

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integral of (\sqrt[3]{x})/(x^2)

- \frac{3}{2 x ^{\frac{2}{3}}} + C

Solution steps

Simplify

= \int \frac{1}{x ^{\frac{5}{3}}} d x

Apply the Power Rule

: - \frac{3}{2 x ^{\frac{2}{3}}}

= - \frac{3}{2 x ^{\frac{2}{3}}}

Add a constant to the solution

= - \frac{3}{2 x ^{\frac{2}{3}}} + C

x \to 4 lim (\frac{2}{( x - 4 ) ^{2}})

\int \frac{1}{25 + 16 x ^{2}} d x

\int_{- 1}^{1} (\frac{1}{x ^{2} + 1}) d x

\frac{\partial}{\partial x} (x^{\frac{3}{4}} y^{\frac{1}{4}})

x \to 0 - lim (\frac{1}{e ^{\frac{1}{x}} - 1})

What is the integral of (\sqrt[3]{x})/(x^2) ?
The integral of (\sqrt[3]{x})/(x^2) is -3/(2x^{2/3)}+C