What is the sum from k=1 to infinity of k^kx^k ?

The sum from k=1 to infinity of k^kx^k is Radius of convergence is 0, Interval of convergence is x=0

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sum from k=1 to infinity of k^kx^k

k = 1 \sum \infty k^{k} x^{k}

Radius of convergence is 0, Interval of convergence is x = 0

Solution steps

k = 1 \sum \infty k^{k} x^{k}

Use the Root Test to compute the convergence interval

Radius of convergence is 0, Interval of convergence is x = 0

\frac{d}{d x} (\frac{2 x + 1}{2 x})

x^{2} - 2 x, - x^{2} + 4 x

\int \frac{2}{x + 2} d x

f (x) = 2 x + 1 + \frac{6}{x}, at x = 2

sin (4 x)

What is the sum from k=1 to infinity of k^kx^k ?
The sum from k=1 to infinity of k^kx^k is Radius of convergence is 0, Interval of convergence is x=0