What is the integral of (ln(16x))^2 ?

The integral of (ln(16x))^2 is xln^2(16x)-2(xln(16x)-x)+C

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integral of (ln(16x))^2

\int (ln (16 x))^{2} d x

x ln^{2} (16 x) - 2 (x ln (16 x) - x) + C

Solution steps

\int (ln (16 x))^{2} d x

Apply Integration By Parts

: x ln^{2} (16 x) - \int 2 ln (16 x) d x

= x ln^{2} (16 x) - \int 2 ln (16 x) d x

\int 2 ln (16 x) d x = 2 (x ln (16 x) - x)

= x ln^{2} (16 x) - 2 (x ln (16 x) - x)

Add a constant to the solution

= x ln^{2} (16 x) - 2 (x ln (16 x) - x) + C

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What is the integral of (ln(16x))^2 ?
The integral of (ln(16x))^2 is xln^2(16x)-2(xln(16x)-x)+C