What is the tangent of 2x^2+x-3,\at x=-1 ?

The tangent of 2x^2+x-3,\at x=-1 is y=-3x-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of 2x^2+x-3,\at x=-1

tangent of

2 x^{2} + x - 3, at x = - 1

y = - 3 x - 5

Solution steps

Find the tangent point:

(- 1, - 2)

Find the slope of

y = 2 x^{2} + x - 3 : \frac{d y}{d x} = 4 x + 1

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 3

Find the line with slope m=

- 3

and passing through

(- 1, - 2) : y = - 3 x - 5

y = - 3 x - 5

\int \frac{z}{1 - y ^{2} z ^{2}} d y

y = \frac{x}{7} - \frac{7}{x}

θ \to 0 lim (\frac{s}{d})

x \to 0 lim (x ln (x) - x)

3 + t^{5} + sin (π t)

What is the tangent of 2x^2+x-3,\at x=-1 ?
The tangent of 2x^2+x-3,\at x=-1 is y=-3x-5