What is the solution for (dy}{dx}=\frac{x-2)/x ?

The solution for (dy}{dx}=\frac{x-2)/x is y=x-2ln(x)+c_{1}

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(dy}{dx}=\frac{x-2)/x

\frac{d y}{d x} = \frac{x - 2}{x}

y = x - 2 ln (x) + c_{1}

Solution steps

\frac{d y}{d x} = \frac{x - 2}{x}

Substitute

\frac{d y}{d x}

with

y^{'} (x)

y^{^{'}} (x) = \frac{x - 2}{x}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int \frac{x - 2}{x} d x

\int \frac{x - 2}{x} d x = x - 2 ln (x) + c_{1}

y = x - 2 ln (x) + c_{1}

\frac{\partial}{\partial y} (\frac{2 y}{( x + y ) ^{2}})

7 e^{x}

\frac{d x}{d t} = k (60 - x)

\int x 1 + x x d x

f (x) = (2 x - 1)^{2}

What is the solution for (dy}{dx}=\frac{x-2)/x ?
The solution for (dy}{dx}=\frac{x-2)/x is y=x-2ln(x)+c_{1}