What is (\partial)/(\partial x)(y^4cos(4x)*4) ?

The answer to (\partial)/(\partial x)(y^4cos(4x)*4) is -16y^4sin(4x)

Popular >

(\partial)/(\partial x)(y^4cos(4x)*4)

\frac{\partial}{\partial x} (y^{4} cos (4 x) \cdot 4)

- 16 y^{4} sin (4 x)

Solution steps

\frac{\partial}{\partial x} (y^{4} cos (4 x) \cdot 4)

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y^{4} \cdot 4 \frac{\partial}{\partial x} (cos (4 x))

Apply the chain rule:

- sin (4 x) \frac{\partial}{\partial x} (4 x)

= - sin (4 x) \frac{\partial}{\partial x} (4 x)

\frac{\partial}{\partial x} (4 x) = 4

= y^{4} \cdot 4 (- sin (4 x) \cdot 4)

Simplify

= - 16 y^{4} sin (4 x)

\int \frac{x ^{2} - 49}{x} d x

x + y^{2} = 2, x + y = 0

\int_{0}^{3 π} 6 x^{2} sin (\frac{1}{6} x) d x

\int_{0}^{6} - x^{2} + 6 x d x

20 x^{3}

What is (\partial)/(\partial x)(y^4cos(4x)*4) ?
The answer to (\partial)/(\partial x)(y^4cos(4x)*4) is -16y^4sin(4x)