What is the derivative of f(x)=8x-3x^2 ?

The derivative of f(x)=8x-3x^2 is 8-6x

What is the first derivative of f(x)=8x-3x^2 ?

The first derivative of f(x)=8x-3x^2 is 8-6x

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derivative of

f (x) = 8 x - 3 x^{2}

8 - 6 x

Solution steps

\frac{d}{d x} (8 x - 3 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x) - \frac{d}{d x} (3 x^{2})

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (3 x^{2}) = 6 x

= 8 - 6 x

(x^{2} + 1) \cdot \frac{d y}{d x} + 6 x (y - 1) = 0, y (0) = 3

\frac{d y}{d t} = \frac{1}{2 y + 1}

f (x) = \frac{x}{x + 1}, at x = 1

\frac{d}{d x} (2 x^{2} y)

(x^{2} - x) \cdot e^{- x}

What is the derivative of f(x)=8x-3x^2 ?
The derivative of f(x)=8x-3x^2 is 8-6x
What is the first derivative of f(x)=8x-3x^2 ?
The first derivative of f(x)=8x-3x^2 is 8-6x