What is the integral of sin(t)cos(t) ?

The integral of sin(t)cos(t) is (sin^2(t))/2+C

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integral of sin(t)cos(t)

\int sin (t) cos (t) d t

\frac{sin ^{2} ( t )}{2} + C

Solution steps

\int sin (t) cos (t) d t

Apply u-substitution

: \int u d u

= \int u d u

Apply the Power Rule

: \frac{u ^{2}}{2}

= \frac{u ^{2}}{2}

Substitute back

u = sin (t)

= \frac{sin ^{2} ( t )}{2}

Add a constant to the solution

= \frac{sin ^{2} ( t )}{2} + C

x \to 0.1 lim (\frac{8 sin ( x )}{x})

2 x^{4} 25 - x^{2}

y^{^{''''}} + 1 = 0

\frac{\partial}{\partial x} (\frac{4}{x y} - x^{2} + 3 y^{2})

\frac{d}{d x} (\frac{1 + x ^{2}}{( 1 - x ^{2} ) ^{2}})

What is the integral of sin(t)cos(t) ?
The integral of sin(t)cos(t) is (sin^2(t))/2+C