What is the solution for 9x(dy)/(dx)=2xe^x-9y+6x^2 ?

The solution for 9x(dy)/(dx)=2xe^x-9y+6x^2 is y=(2(e^xx-e^x)}{9x}+\frac{2x^2)/9+(c_{1})/x

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9x(dy)/(dx)=2xe^x-9y+6x^2

9 x \frac{d y}{d x} = 2 x e^{x} - 9 y + 6 x^{2}

y = \frac{2 ( e ^{x} x - e ^{x} )}{9 x} + \frac{2 x ^{2}}{9} + \frac{c _{1}}{x}

Solution steps

9 x \frac{d y}{d x} = 2 x e^{x} - 9 y + 6 x^{2}

Solve linear ODE:

y = \frac{2 ( e ^{x} x - e ^{x} )}{9 x} + \frac{2 x ^{2}}{9} + \frac{c _{1}}{x}

y = \frac{2 ( e ^{x} x - e ^{x} )}{9 x} + \frac{2 x ^{2}}{9} + \frac{c _{1}}{x}

\frac{d}{d x} (\frac{2 π - x \cdot cos ( x )}{x - 2 π})

\int (- 2) (7 x) d x

\frac{d}{d x} (\frac{4 e ^{x}}{ln ( x )})

\int y^{2} cos (x) - 3 x^{2} y - 2 x d x

\frac{\partial}{\partial x} (e^{- 7 x} cos (10 x))

What is the solution for 9x(dy)/(dx)=2xe^x-9y+6x^2 ?
The solution for 9x(dy)/(dx)=2xe^x-9y+6x^2 is y=(2(e^xx-e^x)}{9x}+\frac{2x^2)/9+(c_{1})/x