What is the tangent of f(x)=10-4e^x,(0,6) ?

The tangent of f(x)=10-4e^x,(0,6) is y=-4x+6

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tangent of f(x)=10-4e^x,(0,6)

tangent of

f (x) = 10 - 4 e^{x}, (0, 6)

y = - 4 x + 6

Solution steps

Find the slope of

f (x) = 10 - 4 e^{x} : \frac{df ( x )}{d x} = - 4 e^{x}

Compute the slope of

f (x) = 10 - 4 e^{x}

(0, 6) : m = - 4

Find the line with slope m=

- 4

and passing through

(0, 6) : y = - 4 x + 6

y = - 4 x + 6

\frac{d}{d x} (sin (4))

\frac{d}{d x} (ln (x - 1) + 1)

x \to 2 lim (x ln (\frac{x}{x - 2}))

f (x) = 4 x^{2} + 5 x + 17

\frac{d}{d x} (4 x - 6)

What is the tangent of f(x)=10-4e^x,(0,6) ?
The tangent of f(x)=10-4e^x,(0,6) is y=-4x+6