What is the solution for t^2y^{''}-7ty^'+15y=0 ?

The solution for t^2y^{''}-7ty^'+15y=0 is y=c_{1}t^5+c_{2}t^3

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t^2y^{''}-7ty^'+15y=0

t^{2} y^{^{''}} - 7 t y^{^{'}} + 15 y = 0

y = c_{1} t^{5} + c_{2} t^{3}

Solution steps

t^{2} y^{''} (t) - 7 t y^{'} (t) + 15 y = 0

Solve linear ODE:

y = c_{1} t^{5} + c_{2} t^{3}

y = c_{1} t^{5} + c_{2} t^{3}

x \to \infty lim (x ln (x))

\frac{s ^{2}}{s ^{3} - 1}

\int x (3 x + 2) d x

\int x sinh (x) d x

\int_{0}^{1} 6 (1 + x)^{5} d x

What is the solution for t^2y^{''}-7ty^'+15y=0 ?
The solution for t^2y^{''}-7ty^'+15y=0 is y=c_{1}t^5+c_{2}t^3