What is the solution for y^{''}-y=3e^x ?

The solution for y^{''}-y=3e^x is y=c_{1}e^x+c_{2}e^{-x}+(3e^xx)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-y=3e^x

y^{^{''}} - y = 3 e^{x}

y = c_{1} e^{x} + c_{2} e^{- x} + \frac{3 e ^{x} x}{2}

Solution steps

y^{''} (x) - y = 3 e^{x}

Solve linear ODE:

y = c_{1} e^{x} + c_{2} e^{- x} + \frac{3 e ^{x} x}{2}

y = c_{1} e^{x} + c_{2} e^{- x} + \frac{3 e ^{x} x}{2}

\frac{d}{d x} ((\frac{1}{x ^{2}} + 3) (x^{2} - \frac{1}{x ^{2}} + 3))

n \to \infty lim (\frac{( - 1 ) ^{n + 1}}{2 n - 1})

\int_{0}^{\frac{π}{2}} sin^{5} (x co) s^{12} x

\frac{\partial}{\partial x} (x^{\frac{1}{2}} \cdot y^{\frac{1}{2}})

\frac{d}{d x} (e^{- x^{2}} + 1)

What is the solution for y^{''}-y=3e^x ?
The solution for y^{''}-y=3e^x is y=c_{1}e^x+c_{2}e^{-x}+(3e^xx)/2