What is the derivative of f(x)=6x^3-9x+4 ?

The derivative of f(x)=6x^3-9x+4 is 18x^2-9

What is the first derivative of f(x)=6x^3-9x+4 ?

The first derivative of f(x)=6x^3-9x+4 is 18x^2-9

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derivative of

f (x) = 6 x^{3} - 9 x + 4

18 x^{2} - 9

Solution steps

\frac{d}{d x} (6 x^{3} - 9 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 x^{3}) - \frac{d}{d x} (9 x) + \frac{d}{d x} (4)

\frac{d}{d x} (6 x^{3}) = 18 x^{2}

\frac{d}{d x} (9 x) = 9

\frac{d}{d x} (4) = 0

= 18 x^{2} - 9 + 0

Simplify

= 18 x^{2} - 9

\frac{x + 1}{x + 4}

n = 0 \sum \infty 5 (\frac{2}{3})^{n}

\int_{1}^{9} (x - x) d x

\frac{d}{d x} (ln (\frac{1 - x}{1 + x}))

f (x) = x^{4} - 8 x^{2} + 5 x + 4, at x = 1

What is the derivative of f(x)=6x^3-9x+4 ?
The derivative of f(x)=6x^3-9x+4 is 18x^2-9
What is the first derivative of f(x)=6x^3-9x+4 ?
The first derivative of f(x)=6x^3-9x+4 is 18x^2-9