What is the derivative of sqrt(r^2-8x^2) ?

The derivative of sqrt(r^2-8x^2) is (r\frac{dr)/(dx)-8x}{sqrt(r^2-8x^2)}

What is the first derivative of sqrt(r^2-8x^2) ?

The first derivative of sqrt(r^2-8x^2) is (r\frac{dr)/(dx)-8x}{sqrt(r^2-8x^2)}

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\frac{d}{d x} (r^{2} - 8 x^{2})

\frac{r \frac{d r}{d x} - 8 x}{r ^{2} - 8 x ^{2}}

Solution steps

\frac{d}{d x} (r^{2} - 8 x^{2})

Apply the chain rule:

\frac{1}{2 r ^{2} - 8 x ^{2}} \frac{d}{d x} (r^{2} - 8 x^{2})

= \frac{1}{2 r ^{2} - 8 x ^{2}} \frac{d}{d x} (r^{2} - 8 x^{2})

\frac{d}{d x} (r^{2} - 8 x^{2}) = 2 r \frac{d r}{d x} - 16 x

= \frac{1}{2 r ^{2} - 8 x ^{2}} (2 r \frac{d r}{d x} - 16 x)

Simplify

\frac{1}{2 r ^{2} - 8 x ^{2}} (2 r \frac{d r}{d x} - 16 x) : \frac{r \frac{d r}{d x} - 8 x}{r ^{2} - 8 x ^{2}}

= \frac{r \frac{d r}{d x} - 8 x}{r ^{2} - 8 x ^{2}}

\int x (x + 4)^{- \frac{3}{2}} d x

n = 1 \sum \infty (- 1)^{n} n^{- 3}

\int \frac{1}{x ^{2} x ^{2} - 81} d x

\int_{- 1}^{3} (- x^{3} + 3 x^{2} + 1) d x

\frac{- 8 x}{y} = 0

What is the derivative of sqrt(r^2-8x^2) ?
The derivative of sqrt(r^2-8x^2) is (r\frac{dr)/(dx)-8x}{sqrt(r^2-8x^2)}
What is the first derivative of sqrt(r^2-8x^2) ?
The first derivative of sqrt(r^2-8x^2) is (r\frac{dr)/(dx)-8x}{sqrt(r^2-8x^2)}