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Popular >

integral of (x+4)^2

Solution

\int (x + 4)^{2} d x

Solution

\frac{x ^{3}}{3} + 4 x^{2} + 16 x + C

Solution steps

\int (x + 4)^{2} d x

Expand

(x + 4)^{2} : x^{2} + 8 x + 16

= \int x^{2} + 8 x + 16 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x + \int 8 x d x + \int 16 d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 8 x d x = 4 x^{2}

\int 16 d x = 16 x

= \frac{x ^{3}}{3} + 4 x^{2} + 16 x

Add a constant to the solution

= \frac{x ^{3}}{3} + 4 x^{2} + 16 x + C

Graph

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Frequently Asked Questions (FAQ)

What is the integral of (x+4)^2 ?
The integral of (x+4)^2 is (x^3)/3+4x^2+16x+C