What is the solution for (y+2xe^{-y/x})dx-xdy=0 ?

The solution for (y+2xe^{-y/x})dx-xdy=0 is y=ln(2ln(x)+c_{1})x

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(y+2xe^{-y/x})dx-xdy=0

(y + 2 x e^{- \frac{y}{x}}) d x - x d y = 0

y = ln (2 ln (x) + c_{1}) x

Solution steps

(y + 2 x e^{- \frac{y}{x}}) d x - x d y = 0

Solve using substitution:

y = ln (2 ln (x) + c_{1}) x

y = ln (2 ln (x) + c_{1}) x

f (x) = \frac{4 x - 5}{x}

x^{2} + 10 x + 25, - 2 x - 2, - 5, - 1

\int (4 x + 8) sin (x^{2} + 4 x - 2) d x

y = ln (x + x^{2} - 3)

\frac{d y}{d x} + 5 y - 20 = 0

What is the solution for (y+2xe^{-y/x})dx-xdy=0 ?
The solution for (y+2xe^{-y/x})dx-xdy=0 is y=ln(2ln(x)+c_{1})x