What is the solution for y^3-(14x+8)+3xy^2(dy)/(dx)=0 ?

The solution for y^3-(14x+8)+3xy^2(dy)/(dx)=0 is y=\sqrt[3]{8+7x+(c_{1})/x}

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y^3-(14x+8)+3xy^2(dy)/(dx)=0

y^{3} - (14 x + 8) + 3 x y^{2} \frac{d y}{d x} = 0

y = 3 8 + 7 x + \frac{c _{1}}{x}

Solution steps

y^{3} - (14 x + 8) + 3 x y^{2} \frac{d y}{d x} = 0

Solve Bernoulli ODE:

y = 3 8 + 7 x + \frac{c _{1}}{x}

y = 3 8 + 7 x + \frac{c _{1}}{x}

\frac{\partial}{\partial y} (sin (x y) + e^{x y})

\int_{- 7}^{7} \frac{y}{49 - y ^{2}} d y

4 arcsin (x^{3})

\int_{0}^{2} (x 9 - x^{2}) d x

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What is the solution for y^3-(14x+8)+3xy^2(dy)/(dx)=0 ?
The solution for y^3-(14x+8)+3xy^2(dy)/(dx)=0 is y=\sqrt[3]{8+7x+(c_{1})/x}