What is the derivative of 9cos^2(t) ?

The derivative of 9cos^2(t) is -18cos(t)sin(t)

What is the first derivative of 9cos^2(t) ?

The first derivative of 9cos^2(t) is -18cos(t)sin(t)

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derivative of

9 cos^{2} (t)

- 18 cos (t) sin (t)

Solution steps

\frac{d}{d t} (9 cos^{2} (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d t} (cos^{2} (t))

Apply the chain rule:

2 cos (t) \frac{d}{d t} (cos (t))

= 2 cos (t) \frac{d}{d t} (cos (t))

\frac{d}{d t} (cos (t)) = - sin (t)

= 9 \cdot 2 cos (t) (- sin (t))

Simplify

= - 18 cos (t) sin (t)

x^{3} - 1

\frac{\partial}{\partial x} (e^{y} + x + x^{2} + 5)

\frac{\partial}{\partial x} (\frac{2 y}{x ^{2} + 2})

y = 3 t + 4 t^{3}

\int \frac{x}{( 4 x ^{2} + 3 ) ^{2}} d x

What is the derivative of 9cos^2(t) ?
The derivative of 9cos^2(t) is -18cos(t)sin(t)
What is the first derivative of 9cos^2(t) ?
The first derivative of 9cos^2(t) is -18cos(t)sin(t)