What is the limit as x approaches 0+of-1/(sin(2x)) ?

The limit as x approaches 0+of-1/(sin(2x)) is -infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0+of-1/(sin(2x))

x \to 0 + lim (- \frac{1}{sin ( 2 x )})

- \infty

Solution steps

x \to 0 + lim (- \frac{1}{sin ( 2 x )})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= - x \to 0 + lim (\frac{1}{sin ( 2 x )})

For

x

approaching

0

from the right

, x > 0 \Rightarrow sin (2 x) > 0

The denominator is a positive quantity approaching 0 from the right

= - \infty

4 (t + 3)

\frac{d}{d x} (y x^{y - 1})

\int \frac{2 sin ( x ) cos ( x )}{1 + tan ( x )} d x

y^{^{''}} + y^{^{'}} = 1

\int_{0}^{1} \frac{e ^{\frac{1}{x}}}{x ^{3}} d x

What is the limit as x approaches 0+of-1/(sin(2x)) ?
The limit as x approaches 0+of-1/(sin(2x)) is -infinity