What is (\partial)/(\partial y)(sin(x+2y)) ?

The answer to (\partial)/(\partial y)(sin(x+2y)) is cos(x+2y)*2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(sin(x+2y))

\frac{\partial}{\partial y} (sin (x + 2 y))

cos (x + 2 y) \cdot 2

Solution steps

\frac{\partial}{\partial y} (sin (x + 2 y))

Treat

x

as a constant

Apply the chain rule:

cos (x + 2 y) \frac{\partial}{\partial y} (x + 2 y)

= cos (x + 2 y) \frac{\partial}{\partial y} (x + 2 y)

\frac{\partial}{\partial y} (x + 2 y) = 2

= cos (x + 2 y) \cdot 2

\int_{0}^{π} 2 π x sin (x) d x

\frac{\partial}{\partial x} ((x y)^{5})

\frac{d}{d x} (x^{2} \cdot I n (x))

f (x) = (1 + 2 x) (6 - 5 x), at x = 1

\frac{\partial}{\partial x} (2 ln (x y))

What is (\partial)/(\partial y)(sin(x+2y)) ?
The answer to (\partial)/(\partial y)(sin(x+2y)) is cos(x+2y)*2