What is the derivative of f(x)=x+3+4/x ?

The derivative of f(x)=x+3+4/x is -4/(x^2)+1

What is the first derivative of f(x)=x+3+4/x ?

The first derivative of f(x)=x+3+4/x is -4/(x^2)+1

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derivative of

f (x) = x + 3 + \frac{4}{x}

- \frac{4}{x ^{2}} + 1

Solution steps

\frac{d}{d x} (x + 3 + \frac{4}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (3) + \frac{d}{d x} (\frac{4}{x})

\frac{d x}{d x} = 1

\frac{d}{d x} (3) = 0

\frac{d}{d x} (\frac{4}{x}) = - \frac{4}{x ^{2}}

= 1 + 0 - \frac{4}{x ^{2}}

Simplify

= - \frac{4}{x ^{2}} + 1

\frac{d}{d t} (- 1)

\int \frac{26}{x ( x ^{2} + 4 ) ^{2}} d x

\frac{1}{( s + 1 ) ^{2} ( s ^{2} + 4 )}

\int \frac{1}{9 x ^{2} - 144} d x

y = x + 2, y = \frac{1}{x + 1}, x = 2

What is the derivative of f(x)=x+3+4/x ?
The derivative of f(x)=x+3+4/x is -4/(x^2)+1
What is the first derivative of f(x)=x+3+4/x ?
The first derivative of f(x)=x+3+4/x is -4/(x^2)+1