What is the integral of (ye^x+sin(y)) ?

The integral of (ye^x+sin(y)) is sin(y)x+ye^x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (ye^x+sin(y))

\int (y e^{x} + sin (y)) d x

sin (y) x + y e^{x} + C

Solution steps

\int y e^{x} + sin (y) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int sin (y) d x + \int y e^{x} d x

\int sin (y) d x = sin (y) x

\int y e^{x} d x = y e^{x}

= sin (y) x + y e^{x}

Add a constant to the solution

= sin (y) x + y e^{x} + C

y^{^{''}} + 2 y + 8 = 0

ln (sec (ln (x)))

\int - \frac{1}{u ^{2}} d u

\frac{\partial}{\partial y} (\frac{- y ^{2}}{( x - y ) ^{2}})

\int (x)^{2} d x

What is the integral of (ye^x+sin(y)) ?
The integral of (ye^x+sin(y)) is sin(y)x+ye^x+C