What is the tangent of f(x)= 2/(x^2),(7, 2/49) ?

The tangent of f(x)= 2/(x^2),(7, 2/49) is y=-4/343 x+6/49

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tangent of f(x)= 2/(x^2),(7, 2/49)

tangent of

f (x) = \frac{2}{x ^{2}}, (7, \frac{2}{49})

y = - \frac{4}{343} x + \frac{6}{49}

Solution steps

Find the slope of

f (x) = \frac{2}{x ^{2}} : \frac{df ( x )}{d x} = - \frac{4}{x ^{3}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{4}{343}

Find the line with slope m=

- \frac{4}{343}

and passing through

(7, \frac{2}{49}) : y = - \frac{4}{343} x + \frac{6}{49}

y = - \frac{4}{343} x + \frac{6}{49}

\frac{d}{d x} (ln (3 x^{2} + 1))

\frac{d}{d y} (\frac{y}{y + \frac{b}{y}})

\int 2 x (x^{2} + 1)^{23} d x

n = 1 \sum \infty - \frac{1}{3 ( 3 n + 2 )}

\int \frac{1}{y ln ( y )} d y

What is the tangent of f(x)= 2/(x^2),(7, 2/49) ?
The tangent of f(x)= 2/(x^2),(7, 2/49) is y=-4/343 x+6/49