What is (\partial)/(\partial x)(-5e^xln(y)) ?

The answer to (\partial)/(\partial x)(-5e^xln(y)) is -5ln(y)e^x

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(\partial)/(\partial x)(-5e^xln(y))

\frac{\partial}{\partial x} (- 5 e^{x} ln (y))

- 5 ln (y) e^{x}

Solution steps

\frac{\partial}{\partial x} (- 5 e^{x} ln (y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 5 ln (y) \frac{\partial}{\partial x} (e^{x})

Apply the common derivative:

\frac{\partial}{\partial x} (e^{x}) = e^{x}

= - 5 ln (y) e^{x}

y = x^{2}, y = 3 x + 4

- 6

\frac{d}{d t} (e^{t} - 4)

(2 x - y) + (2 y - x) y^{^{'}} = 0, y (1) = 3

\frac{\partial}{\partial y} (e^{x y} sin (z))

What is (\partial)/(\partial x)(-5e^xln(y)) ?
The answer to (\partial)/(\partial x)(-5e^xln(y)) is -5ln(y)e^x