What is the tangent of y=3+4x^2-2x^3,(1,5) ?

The tangent of y=3+4x^2-2x^3,(1,5) is y=2x+3

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tangent of y=3+4x^2-2x^3,(1,5)

tangent of

y = 3 + 4 x^{2} - 2 x^{3}, (1, 5)

y = 2 x + 3

Solution steps

Find the slope of

y = 3 + 4 x^{2} - 2 x^{3} : \frac{d y}{d x} = - 6 x^{2} + 8 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2

Find the line with slope m=

2

and passing through

(1, 5) : y = 2 x + 3

y = 2 x + 3

f (x) = 3 x^{2} e^{x} + e^{x} (x^{3} + 6)

\frac{d}{d x} (7 sec^{2} (7 x))

\frac{d}{d x} (x^{\frac{5}{x}})

\int_{0}^{9} x e^{- x^{2}} d x

\frac{1}{x ^{2}}, 1

What is the tangent of y=3+4x^2-2x^3,(1,5) ?
The tangent of y=3+4x^2-2x^3,(1,5) is y=2x+3