What is the integral of-2/3 y^{-4/3} ?

The integral of-2/3 y^{-4/3} is 2/(y^{1/3)}+C

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integral of-2/3 y^{-4/3}

\int - \frac{2}{3} y^{- \frac{4}{3}} d y

\frac{2}{y ^{\frac{1}{3}}} + C

Solution steps

\int - \frac{2}{3} y^{- \frac{4}{3}} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{2}{3} \cdot \int y^{- \frac{4}{3}} d y

Apply the Power Rule

: - \frac{3}{y ^{\frac{1}{3}}}

= - \frac{2}{3} (- \frac{3}{y ^{\frac{1}{3}}})

Simplify

- \frac{2}{3} (- \frac{3}{y ^{\frac{1}{3}}}) : \frac{2}{y ^{\frac{1}{3}}}

= \frac{2}{y ^{\frac{1}{3}}}

Add a constant to the solution

= \frac{2}{y ^{\frac{1}{3}}} + C

y = \frac{3 cos ( x )}{1 + sin ( x )}

\frac{d}{d x} ((tan (x))^{\frac{1}{2}})

\int_{0}^{l n (3)} e^{x} d x

\int e^{c o s (40 t)} sin (40 t) d t

\frac{d}{d x} (\frac{6 x}{x ^{2} + 36})

What is the integral of-2/3 y^{-4/3} ?
The integral of-2/3 y^{-4/3} is 2/(y^{1/3)}+C