What is the derivative of ax^2+bx^2+c ?

The derivative of ax^2+bx^2+c is 2ax+2bx

What is the first derivative of ax^2+bx^2+c ?

The first derivative of ax^2+bx^2+c is 2ax+2bx

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\frac{d}{d x} (a x^{2} + b x^{2} + c)

2 a x + 2 b x

Solution steps

\frac{d}{d x} (a x^{2} + b x^{2} + c)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a x^{2}) + \frac{d}{d x} (b x^{2}) + \frac{d c}{d x}

\frac{d}{d x} (a x^{2}) = 2 a x

\frac{d}{d x} (b x^{2}) = 2 b x

\frac{d c}{d x} = 0

= 2 a x + 2 b x + 0

Simplify

= 2 a x + 2 b x

\int ln (x) sin (x) d x

\int \frac{2}{x} - \frac{1}{x ^{2}} d x

\int \frac{2 x}{4 x - 5} d x

\frac{d r}{d t} = \frac{r ^{2}}{t}

(- 3 x + 2)^{2}

What is the derivative of ax^2+bx^2+c ?
The derivative of ax^2+bx^2+c is 2ax+2bx
What is the first derivative of ax^2+bx^2+c ?
The first derivative of ax^2+bx^2+c is 2ax+2bx