What is the solution for y^'+(3/(300-x))y=4 ?

The solution for y^'+(3/(300-x))y=4 is y=-2(x-300)+c_{1}(27000000-270000x+900x^2-x^3)

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y^'+(3/(300-x))y=4

y^{^{'}} + (\frac{3}{300 - x}) y = 4

y = - 2 (x - 300) + c_{1} (27000000 - 270000 x + 900 x^{2} - x^{3})

Solution steps

y^{'} (x) + (\frac{3}{300 - x}) y = 4

Solve linear ODE:

y = - 2 (x - 300) + c_{1} (27000000 - 270000 x + 900 x^{2} - x^{3})

y = - 2 (x - 300) + c_{1} (27000000 - 270000 x + 900 x^{2} - x^{3})

f (x) = ln (1 + x)

0.9 x^{3} 5^{x}

\int \frac{( 5 + ln ( x ) ) ^{\frac{2}{3}}}{x} d x

\frac{\partial}{\partial y} (x^{5 y})

\int (x^{5}) d x

What is the solution for y^'+(3/(300-x))y=4 ?
The solution for y^'+(3/(300-x))y=4 is y=-2(x-300)+c_{1}(27000000-270000x+900x^2-x^3)