What is the sum from n=1 to infinity of 2/((n+1)!) ?

The sum from n=1 to infinity of 2/((n+1)!) is converges

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sum from n=1 to infinity of 2/((n+1)!)

n = 1 \sum \infty \frac{2}{( n + 1 ) !}

converges

Solution steps

n = 1 \sum \infty \frac{2}{( n + 1 ) !}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 2 \cdot n = 1 \sum \infty \frac{1}{( n + 1 ) !}

Apply Series Ratio Test:

converges

= 2 converges

= converges

x \to 0 lim (ln ((1 + \frac{1}{x})^{x}))

y^{^{''}} - 10 y^{^{'}} + 41 y = 0

(11, 8), (3, - 8)

e^{x}, 4

\frac{\partial}{\partial y} (4)

What is the sum from n=1 to infinity of 2/((n+1)!) ?
The sum from n=1 to infinity of 2/((n+1)!) is converges