What is the derivative of y= 7/(sqrt(x)) ?

The derivative of y= 7/(sqrt(x)) is -7/(2x^{3/2)}

What is the first derivative of y= 7/(sqrt(x)) ?

The first derivative of y= 7/(sqrt(x)) is -7/(2x^{3/2)}

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derivative of

y = \frac{7}{x}

- \frac{7}{2 x ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{7}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 7 \frac{d}{d x} (x^{- \frac{1}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 7 (- \frac{1}{2} x^{- \frac{1}{2} - 1})

Simplify

7 (- \frac{1}{2} x^{- \frac{1}{2} - 1}) : - \frac{7}{2 x ^{\frac{3}{2}}}

= - \frac{7}{2 x ^{\frac{3}{2}}}

y^{^{''''}} + 4 y = 0

\frac{d}{d x} (3 e^{x} + 8 x^{2} ln^{2} (x))

f (x) = \frac{5}{x ^{11}}

\frac{1}{s ^{2} + 4 s + 13}

\frac{d}{d x} (e^{12 x})

What is the derivative of y= 7/(sqrt(x)) ?
The derivative of y= 7/(sqrt(x)) is -7/(2x^{3/2)}
What is the first derivative of y= 7/(sqrt(x)) ?
The first derivative of y= 7/(sqrt(x)) is -7/(2x^{3/2)}