What is the integral of (1/(cos^2(x))) ?

The integral of (1/(cos^2(x))) is tan(x)+C

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integral of (1/(cos^2(x)))

\int (\frac{1}{cos ^{2} ( x )}) d x

tan (x) + C

Solution steps

\int \frac{1}{cos ^{2} ( x )} d x

Use the common integral:

\int \frac{1}{cos ^{2} ( x )} d x = tan (x)

= tan (x)

Add a constant to the solution

= tan (x) + C

\frac{\partial}{\partial x} (15 - 5 (x + 3)^{2})

\int (y - y) d y

\int \frac{1}{cosh ( x )} d x

y^{^{''}} + 8 y^{^{'}} + 25 y = 0, y (0) = 4, y^{^{'}} (0) = - 14

\int \frac{a}{x} d x

What is the integral of (1/(cos^2(x))) ?
The integral of (1/(cos^2(x))) is tan(x)+C