What is (\partial)/(\partial x)(1-cos(x)) ?

The answer to (\partial)/(\partial x)(1-cos(x)) is sin(x)

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(\partial)/(\partial x)(1-cos(x))

\frac{\partial}{\partial x} (1 - cos (x))

sin (x)

Solution steps

\frac{\partial}{\partial x} (1 - cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (1) - \frac{\partial}{\partial x} (cos (x))

\frac{\partial}{\partial x} (1) = 0

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= 0 - (- sin (x))

Simplify

= sin (x)

\int cos (\frac{π}{2}) d x

- 19.6 t^{2} + 9 t + 3

\frac{d}{d x} (40320)

f (x) = \frac{x ^{3}}{6}

\int_{3}^{6} \frac{x ^{2} - 9}{x} d x

What is (\partial)/(\partial x)(1-cos(x)) ?
The answer to (\partial)/(\partial x)(1-cos(x)) is sin(x)