What is the tangent of f(x)=x^2-2,(2,2) ?

The tangent of f(x)=x^2-2,(2,2) is y=4x-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=x^2-2,(2,2)

tangent of

f (x) = x^{2} - 2, (2, 2)

y = 4 x - 6

Solution steps

Find the slope of

f (x) = x^{2} - 2 : \frac{df ( x )}{d x} = 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 4

Find the line with slope m=

4

and passing through

(2, 2) : y = 4 x - 6

y = 4 x - 6

\frac{d}{d x} (5 x arcsin (x))

x \to \infty lim (0, x)

n = 1 \sum \infty \frac{2}{3} (\frac{1}{3})^{n}

\int \frac{1}{( x ^{2} + 2 x + 2 )} d x

\int \frac{x}{x - 7} d x

What is the tangent of f(x)=x^2-2,(2,2) ?
The tangent of f(x)=x^2-2,(2,2) is y=4x-6