What is the derivative of 40sqrt(x)-4x ?

The derivative of 40sqrt(x)-4x is (20)/(sqrt(x))-4

What is the first derivative of 40sqrt(x)-4x ?

The first derivative of 40sqrt(x)-4x is (20)/(sqrt(x))-4

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\frac{d}{d x} (40 x - 4 x)

\frac{20}{x} - 4

Solution steps

\frac{d}{d x} (40 x - 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (40 x) - \frac{d}{d x} (4 x)

\frac{d}{d x} (40 x) = \frac{20}{x}

\frac{d}{d x} (4 x) = 4

= \frac{20}{x} - 4

\int \frac{1}{( x ^{2} + 16 ) ^{\frac{3}{2}}} d x

f (x) = x^{2} - 3, at x = 3

\int_{a}^{2 a} (a x - \frac{a ^{3}}{x}) d x

x \to \infty lim (4 e^{- 4 x})

\int x^{\frac{6}{5}} d x

What is the derivative of 40sqrt(x)-4x ?
The derivative of 40sqrt(x)-4x is (20)/(sqrt(x))-4
What is the first derivative of 40sqrt(x)-4x ?
The first derivative of 40sqrt(x)-4x is (20)/(sqrt(x))-4