What is the derivative of 3x^4-2x^2+8 ?

The derivative of 3x^4-2x^2+8 is 12x^3-4x

What is the first derivative of 3x^4-2x^2+8 ?

The first derivative of 3x^4-2x^2+8 is 12x^3-4x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (3 x^{4} - 2 x^{2} + 8)

12 x^{3} - 4 x

Solution steps

\frac{d}{d x} (3 x^{4} - 2 x^{2} + 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{4}) - \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (8)

\frac{d}{d x} (3 x^{4}) = 12 x^{3}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (8) = 0

= 12 x^{3} - 4 x + 0

Simplify

= 12 x^{3} - 4 x

\frac{d y}{d x} = x^{6} y^{- 3}, y (0) = 4

\int \frac{3 sin ( x ) + 4 sec ( x )}{tan ( x )} d x

f (x) = x^{l o g_{10} (x)}

\int \frac{x}{a x + b} d x

\int_{- 3}^{- 5} (- 5)^{- 3} d x

What is the derivative of 3x^4-2x^2+8 ?
The derivative of 3x^4-2x^2+8 is 12x^3-4x
What is the first derivative of 3x^4-2x^2+8 ?
The first derivative of 3x^4-2x^2+8 is 12x^3-4x