What is (\partial)/(\partial x)(20-5xy-5x) ?

The answer to (\partial)/(\partial x)(20-5xy-5x) is -5y-5

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(\partial)/(\partial x)(20-5xy-5x)

\frac{\partial}{\partial x} (20 - 5 x y - 5 x)

- 5 y - 5

Solution steps

\frac{\partial}{\partial x} (20 - 5 x y - 5 x)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (20) - \frac{\partial}{\partial x} (5 x y) - \frac{\partial}{\partial x} (5 x)

\frac{\partial}{\partial x} (20) = 0

\frac{\partial}{\partial x} (5 x y) = 5 y

\frac{\partial}{\partial x} (5 x) = 5

= 0 - 5 y - 5

Simplify

= - 5 y - 5

x \to 2 + lim (x - 3)

\int_{1}^{2} \frac{2}{x ^{2}} d x

\frac{d}{d x} (\frac{3 x - x ^{2}}{x} - 4 cot (x))

f (x) = 3 cos (cos (x^{6}))

\int_{- \infty}^{0} \frac{1}{2 - 10 x} d x

What is (\partial)/(\partial x)(20-5xy-5x) ?
The answer to (\partial)/(\partial x)(20-5xy-5x) is -5y-5