What is the limit as x approaches 4 of sqrt(2x-1) ?

The limit as x approaches 4 of sqrt(2x-1) is square root of 7

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limit as x approaches 4 of sqrt(2x-1)

x \to 4 lim (2 x - 1)

7

Decimal

2.64575 \dots

Solution steps

x \to 4 lim (2 x - 1)

Plug in the value

x = 4

= 2 \cdot 4 - 1

Simplify

= 7

\frac{d}{d x} (5 e^{4 x})

\int \frac{sin ^{5} ( x )}{x} d x

\int x^{2} 3 7 x^{3} + 1 d x

x \to - \infty lim (4 e^{- x})

d y - (y - 3)^{2} d x = 0

What is the limit as x approaches 4 of sqrt(2x-1) ?
The limit as x approaches 4 of sqrt(2x-1) is square root of 7