What is area x=2sqrt(3y),x=0,y=7 ?

The answer to area x=2sqrt(3y),x=0,y=7 is -(28sqrt(7))/(sqrt(3))+28sqrt(21)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area x=2sqrt(3y),x=0,y=7

area

x = 2 3 y, x = 0, y = 7

- \frac{28 7}{3} + 2821

Decimal

85.54141 \dots

Solution steps

Isolate

y

for

x = 2 3 y : y = \frac{x ^{2}}{12} {x \geq 0}

Apply the area formula:

\int_{- 221}^{221} \frac{x ^{2}}{12} - 7 d x

Solve

\int_{- 221}^{221} \frac{x ^{2}}{12} - 7 d x : - \frac{28 7}{3} + 2821

The area is:

= - \frac{28 7}{3} + 2821

\frac{( 2 s + 1 )}{s ^{2} + 2 s + 2}

\int - 5 sec^{2} (x) d x

f (x) = x^{3} - 25 x + 5, at x = 5

y^{^{'}} = \frac{( x ^{2} - y ^{2} )}{x y}, y (2) = 4

\int e^{6 u} d u

What is area x=2sqrt(3y),x=0,y=7 ?
The answer to area x=2sqrt(3y),x=0,y=7 is -(28sqrt(7))/(sqrt(3))+28sqrt(21)