What is (\partial)/(\partial y)(e^ycos(x)) ?

The answer to (\partial)/(\partial y)(e^ycos(x)) is cos(x)e^y

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(\partial)/(\partial y)(e^ycos(x))

\frac{\partial}{\partial y} (e^{y} cos (x))

cos (x) e^{y}

Solution steps

\frac{\partial}{\partial y} (e^{y} cos (x))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cos (x) \frac{\partial}{\partial y} (e^{y})

Apply the common derivative:

\frac{\partial}{\partial y} (e^{y}) = e^{y}

= cos (x) e^{y}

x \to 0 lim (e^{x + 1})

\int cos (t - 2 x) d x

\int (6 x^{2} - 3 x) d x

\frac{d}{d x} (lo g_{6} (2 x^{3} - 5 x^{2}))

\int tan^{2} (x se) c^{3} x d x

What is (\partial)/(\partial y)(e^ycos(x)) ?
The answer to (\partial)/(\partial y)(e^ycos(x)) is cos(x)e^y