What is the derivative of arcsin(4x+1) ?

The derivative of arcsin(4x+1) is 4/(sqrt(-16x^2-8x))

What is the first derivative of arcsin(4x+1) ?

The first derivative of arcsin(4x+1) is 4/(sqrt(-16x^2-8x))

Popular >

derivative of

arcsin (4 x + 1)

\frac{4}{- 16 x ^{2} - 8 x}

Solution steps

\frac{d}{d x} (arcsin (4 x + 1))

Apply the chain rule:

\frac{1}{1 - ( 4 x + 1 ) ^{2}} \frac{d}{d x} (4 x + 1)

= \frac{1}{1 - ( 4 x + 1 ) ^{2}} \frac{d}{d x} (4 x + 1)

\frac{d}{d x} (4 x + 1) = 4

= \frac{1}{1 - ( 4 x + 1 ) ^{2}} \cdot 4

Simplify

\frac{1}{1 - ( 4 x + 1 ) ^{2}} \cdot 4 : \frac{4}{- 16 x ^{2} - 8 x}

= \frac{4}{- 16 x ^{2} - 8 x}

\frac{d}{d x} (\frac{x}{2 x ^{2} + 1})

\int (7 + x^{5})^{6} 5 x^{4} d x

\frac{d}{d x} (cos (\frac{1}{2} x))

y^{^{''}} - 16 y^{^{'}} + 64 y = 8 t^{6} e^{8 t}

\frac{d}{d x} (x^{2} + 17)

What is the derivative of arcsin(4x+1) ?
The derivative of arcsin(4x+1) is 4/(sqrt(-16x^2-8x))
What is the first derivative of arcsin(4x+1) ?
The first derivative of arcsin(4x+1) is 4/(sqrt(-16x^2-8x))