What is the integral of (5e^{2x})/(e^{2x)+13e^x+36} ?

The integral of (5e^{2x})/(e^{2x)+13e^x+36} is

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (5e^{2x})/(e^{2x)+13e^x+36}

\int \frac{5 e ^{2 x}}{e ^{2 x} + 13 e ^{x} + 36} d x

10 (\frac{1}{4} ln 52 e^{x} + 4 e^{2 x} + 144 + \frac{13}{20} (ln \frac{18}{5} + \frac{2}{5} e^{x} - ln \frac{8}{5} + \frac{2}{5} e^{x})) + C

Solution steps

\int \frac{5 e ^{2 x}}{e ^{2 x} + 13 e ^{x} + 36} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int \frac{e ^{2 x}}{e ^{2 x} + 13 e ^{x} + 36} d x

Apply u-substitution

: \int \frac{u}{u ^{2} + 13 u + 36} d u

= 5 \cdot \int \frac{u}{u ^{2} + 13 u + 36} d u

Complete the square

u^{2} + 13 u + 36 : (u + \frac{13}{2})^{2} - \frac{25}{4}

= 5 \cdot \int \frac{u}{( u + \frac{13}{2} ) ^{2} - \frac{25}{4}} d u

Apply u-substitution

: \int \frac{2 ( 2 v - 13 )}{4 v ^{2} - 25} d v

= 5 \cdot \int \frac{2 ( 2 v - 13 )}{4 v ^{2} - 25} d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot 2 \cdot \int \frac{2 v - 13}{4 v ^{2} - 25} d v

Expand

\frac{2 v - 13}{4 v ^{2} - 25} : \frac{2 v}{4 v ^{2} - 25} - \frac{13}{4 v ^{2} - 25}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 5 \cdot 2 (\int \frac{2 v}{4 v ^{2} - 25} d v - \int \frac{13}{4 v ^{2} - 25} d v)

\int \frac{2 v}{4 v ^{2} - 25} d v = \frac{1}{4} ln 4 v^{2} - 25

\int \frac{13}{4 v ^{2} - 25} d v = - \frac{13}{20} (ln \frac{2}{5} v + 1 - ln \frac{2}{5} v - 1)

= 5 \cdot 2 (\frac{1}{4} ln 4 v^{2} - 25 - (- \frac{13}{20} (ln \frac{2}{5} v + 1 - ln \frac{2}{5} v - 1)))

Substitute back

= 5 \cdot 2 (\frac{1}{4} ln 4 (e^{x} + \frac{13}{2})^{2} - 25 - (- \frac{13}{20} (ln \frac{2}{5} (e^{x} + \frac{13}{2}) + 1 - ln \frac{2}{5} (e^{x} + \frac{13}{2}) - 1)))

Simplify

5 \cdot 2 (\frac{1}{4} ln 4 (e^{x} + \frac{13}{2})^{2} - 25 - (- \frac{13}{20} (ln \frac{2}{5} (e^{x} + \frac{13}{2}) + 1 - ln \frac{2}{5} (e^{x} + \frac{13}{2}) - 1))) : 10 (\frac{1}{4} ln 52 e^{x} + 4 e^{2 x} + 144 + \frac{13}{20} (ln \frac{18}{5} + \frac{2}{5} e^{x} - ln \frac{8}{5} + \frac{2}{5} e^{x}))

= 10 (\frac{1}{4} ln 52 e^{x} + 4 e^{2 x} + 144 + \frac{13}{20} (ln \frac{18}{5} + \frac{2}{5} e^{x} - ln \frac{8}{5} + \frac{2}{5} e^{x}))

Add a constant to the solution

= 10 (\frac{1}{4} ln 52 e^{x} + 4 e^{2 x} + 144 + \frac{13}{20} (ln \frac{18}{5} + \frac{2}{5} e^{x} - ln \frac{8}{5} + \frac{2}{5} e^{x})) + C

\int_{0}^{1} π (x^{3})^{2} d x

\int y e^{- x^{2}} d x

(- 5, - 3), (5, 2)

\int_{0}^{2 π} 2 a (sin (\frac{t}{2})) d t

n = 1 \sum \infty n^{2} \cdot x^{n}

What is the integral of (5e^{2x})/(e^{2x)+13e^x+36} ?
The integral of (5e^{2x})/(e^{2x)+13e^x+36} is