What is the limit as z approaches 0 of 1/(1+1/z) ?

The limit as z approaches 0 of 1/(1+1/z) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as z approaches 0 of 1/(1+1/z)

z \to 0 lim (\frac{1}{1 + \frac{1}{z}})

0

Solution steps

z \to 0 lim (\frac{1}{1 + \frac{1}{z}})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

z \to 0 - lim (\frac{1}{1 + \frac{1}{z}}) = 0

z \to 0 + lim (\frac{1}{1 + \frac{1}{z}}) = 0

= 0

4 x^{2}, 40 x - 100, 0, 5

\frac{d y}{d x} + 2 x y^{2} = 0

\frac{d}{d x} (e^{\frac{x}{x - 3}})

x \to 8 lim (x^{2} - 5 x - 11)

\frac{d y}{d x} = 5 x^{4} - sec^{2} (x)

What is the limit as z approaches 0 of 1/(1+1/z) ?
The limit as z approaches 0 of 1/(1+1/z) is 0