What is (\partial)/(\partial x)(2x^2+y^2) ?

The answer to (\partial)/(\partial x)(2x^2+y^2) is 4x

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(\partial)/(\partial x)(2x^2+y^2)

\frac{\partial}{\partial x} (2 x^{2} + y^{2})

4 x

Solution steps

\frac{\partial}{\partial x} (2 x^{2} + y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x^{2}) + \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (2 x^{2}) = 4 x

\frac{\partial}{\partial x} (y^{2}) = 0

= 4 x + 0

Simplify

= 4 x

n \to \infty lim (1.0 4^{n})

\frac{d}{d x} (- x^{3} + 6 x^{2} - 9 x)

\int \frac{- 5}{x ^{2} + 16} d x

\int \frac{2 e ^{- \frac{6}{x ^{4}}}}{x ^{5}} d x

\frac{d ^{2} y}{d t ^{2}} - 8 \frac{d y}{d t} + 16 y = 0

What is (\partial)/(\partial x)(2x^2+y^2) ?
The answer to (\partial)/(\partial x)(2x^2+y^2) is 4x