What is the solution for (x+y)dx+(x+y-1)dy=0 ?

The solution for (x+y)dx+(x+y-1)dy=0 is y=1-x+sqrt(-2x+c_{1)+1},y=1-x-sqrt(-2x+c_{1)+1}

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(x+y)dx+(x+y-1)dy=0

(x + y) d x + (x + y - 1) d y = 0

y = 1 - x + - 2 x + c_{1} + 1, y = 1 - x - - 2 x + c_{1} + 1

Solution steps

(x + y) d x + (x + y - 1) d y = 0

Solve exact ODE:

y = 1 - x + - 2 x + c_{1} + 1, y = 1 - x - - 2 x + c_{1} + 1

y = 1 - x + - 2 x + c_{1} + 1, y = 1 - x - - 2 x + c_{1} + 1

\int (\frac{- y}{x ^{2} + y ^{2}}) d x

\frac{\partial}{\partial x} ((x - y) sin (3 x + 2 y))

\frac{6}{( s ^{2} ( s ^{2} + 8 s + 1 ) )}

y = ln ∣ x ∣

f (x) = x - 8, at x = 12

What is the solution for (x+y)dx+(x+y-1)dy=0 ?
The solution for (x+y)dx+(x+y-1)dy=0 is y=1-x+sqrt(-2x+c_{1)+1},y=1-x-sqrt(-2x+c_{1)+1}