What is the derivative of y=ln(18x^2-5x+11) ?

The derivative of y=ln(18x^2-5x+11) is (36x-5)/(18x^2-5x+11)

What is the first derivative of y=ln(18x^2-5x+11) ?

The first derivative of y=ln(18x^2-5x+11) is (36x-5)/(18x^2-5x+11)

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derivative of

y = ln (18 x^{2} - 5 x + 11)

\frac{36 x - 5}{18 x ^{2} - 5 x + 11}

Solution steps

\frac{d}{d x} (ln (18 x^{2} - 5 x + 11))

Apply the chain rule:

\frac{1}{18 x ^{2} - 5 x + 11} \frac{d}{d x} (18 x^{2} - 5 x + 11)

= \frac{1}{18 x ^{2} - 5 x + 11} \frac{d}{d x} (18 x^{2} - 5 x + 11)

\frac{d}{d x} (18 x^{2} - 5 x + 11) = 36 x - 5

= \frac{1}{18 x ^{2} - 5 x + 11} (36 x - 5)

Simplify

\frac{1}{18 x ^{2} - 5 x + 11} (36 x - 5) : \frac{36 x - 5}{18 x ^{2} - 5 x + 11}

= \frac{36 x - 5}{18 x ^{2} - 5 x + 11}

2^{x + 3}

\int \frac{x ^{3}}{3 x ^{2} + 3} d x

Y^{3}

\int \frac{y}{4} d y

\int 3 x^{2} - 2 x y d x

What is the derivative of y=ln(18x^2-5x+11) ?
The derivative of y=ln(18x^2-5x+11) is (36x-5)/(18x^2-5x+11)
What is the first derivative of y=ln(18x^2-5x+11) ?
The first derivative of y=ln(18x^2-5x+11) is (36x-5)/(18x^2-5x+11)