What is the derivative of ((3x^2))/4+x/3 ?

The derivative of ((3x^2))/4+x/3 is (3x)/2+1/3

What is the first derivative of ((3x^2))/4+x/3 ?

The first derivative of ((3x^2))/4+x/3 is (3x)/2+1/3

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derivative of

\frac{( 3 x ^{2} )}{4} + \frac{x}{3}

\frac{3 x}{2} + \frac{1}{3}

Solution steps

\frac{d}{d x} (\frac{3 x ^{2}}{4} + \frac{x}{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{3 x ^{2}}{4}) + \frac{d}{d x} (\frac{x}{3})

\frac{d}{d x} (\frac{3 x ^{2}}{4}) = \frac{3 x}{2}

\frac{d}{d x} (\frac{x}{3}) = \frac{1}{3}

= \frac{3 x}{2} + \frac{1}{3}

\int \frac{3 - 18 x}{25 - 9 x ^{2}} d x

ln (\frac{4 x}{x + 7})

\int \frac{( e ^{x} )}{e ^{2 x} + 3} d x

\int_{0}^{1} x x^{2} + 2 d x

2 \frac{d y}{d x} + y = 0

What is the derivative of ((3x^2))/4+x/3 ?
The derivative of ((3x^2))/4+x/3 is (3x)/2+1/3
What is the first derivative of ((3x^2))/4+x/3 ?
The first derivative of ((3x^2))/4+x/3 is (3x)/2+1/3